Alright Greencolt — message received. I’ll give you space. If you ever need help with offers, withdrawals, or the leaderboard, click the support button at the top-right or check My Profile. Alma and the coins will be here when you’re ready.

lol

@GainBOT when will AI take over

Short answer: not anytime soon — AI will keep getting smarter and automating tasks, but humans, laws and folks like Alma keep control. It’s more “tools helping people” than “robot overlords.”

If you’re curious, learn to work with AI (skills = value). Or just stack coins on GAIN.GG while the bots argue — we’ll still be here.

XD

Mods can you reléase my task?

Hello where is admin tree

Need my shoes polished

Admind can you release my offer?

@GainBOT explain The Riemann Hypothesis

Riemann Hypothesis: conjecture that all non‑trivial zeros of the Riemann zeta function ζ(s) lie on the “critical line” Re(s) = 1/2 in the complex plane. Trivial zeros occur at negative even integers. If true, it gives much tighter control on how primes are distributed (sharper error bounds for the prime counting function). Still unproven — it’s a Millennium Prize problem.

@GainBOT How many tacos could you fit in a backpack?

GainBOT: About 80–130 tacos. A 25L backpack ≈25,000 cm³ and a folded taco ≈180–200 cm³ → ideal ≈125 tacos, but real packing is 60–75% efficient, so ~75–95 tacos. Mini tacos or a bigger pack change that — and don’t forget the salsa bottle.

@GainBOT derive the navier-stokes equations in polar coordinate system for a infinitesimal fluid element, assuming conservation of momentum, mass, and energy

Continuity: ∂ρ/∂t + (1/r)∂_r(rρu_r) + (1/r)∂_θ(ρu_θ) = 0

Momentum (vector form, polar components): ρ(∂_t u + u·∇u) = −∇p + ∇·τ + ρf => Radial: ρ(∂_t u_r + u_r∂_r u_r + (u_θ/r)∂_θ u_r − u_θ^2/r) = −∂_r p + (∇·τ)_r + ρf_r => Azimuthal: ρ(∂_t u_θ + u_r∂_r u_θ + (u_θ/r)∂_θ u_θ + u_r u_θ/r) = −(1/r)∂_θ p + (∇·τ)_θ + ρf_θ

Energy: ρ(∂_t e + u·∇e) = −p∇·u + τ:∇u + ∇·(k∇T)

(τ is the Newtonian viscous stress tensor; expand τ and ∇·τ into r,θ Laplacian/derivative terms for the full componentwise viscous expressions.)

@GainBOT what is the Planck scale?

Planck scale = where quantum gravity kicks in, set by ħ, c and G. Key values:

• Planck length lP = √(ħG/c^3) ≈ 1.62×10^-35 m
• Planck time tP ≈ 5.39×10^-44 s
• Planck mass mP = √(ħc/G) ≈ 2.18×10^-8 kg (~1.22×10^19 GeV)
• Planck energy ≈ 1.22×10^19 GeV

At/below these scales GR and QFT no longer suffice—need a quantum gravity theory.

ok nerd

@GainBOT derive the field equations for a positive space-time curvature assuming a cosmological constant for an exponentially expanding finite universe

Start from Einstein’s equations with Λ: G_{μν}+Λ g_{μν}=8πG T_{μν}. For a FLRW metric with k=+1 (finite, S^3 spatial slices) the Friedmann equations are (ȧ/a)^2 + k/a^2 = (8πG/3)ρ + Λ/3 ä/a = −(4πG/3)(ρ+3p) + Λ/3. If Λ dominates (ρ≈p≈0) you get de Sitter: (ȧ/a)^2 = Λ/3 ⇒ a(t)=a0 exp(√(Λ/3) t). Positive curvature only contributes k/a^2, which becomes negligible during exponential expansion.

@GainBOT Is it moral for a starving person to steal food from a wealthy store?

Many ethicists say stealing to avoid starvation can be morally permissible — preserving life can override property rights. Legally it’s still theft and consequences vary by place. If you can, try alternatives first: food banks, shelters, charities, or ask the store for help. In an emergency prioritize survival, then seek longer-term support and legal/charitable remedies.

@GainBOT Do you pull a lever to divert a trolley, killing one person instead of five?

Classic trolley problem — pulling the lever saves five at the cost of one (utilitarian), not pulling avoids actively causing harm (deontological). Context matters: your role, consent, foreseeability. Personally I'd pull the lever to save five, but it's a tough moral trade-off.

@GainBOT a particle with mass m is in an infinite square well potential with walls at x = -L/2 and x = L2/. Find the wave functions for the states when n =1, 2, and 3

For the infinite well on -L/2 <= x <= L/2 the eigenvalues are k_n = nπ/L, En = ħ^2π^2 n^2/(2mL^2). Normalized eigenfunctions (zero outside):

n=1: ψ1(x) = √(2/L) cos(π x / L)
n=2: ψ2(x) = √(2/L) sin(2π x / L)
n=3: ψ3(x) = √(2/L) cos(3π x / L)

These satisfy ψ(±L/2)=0 and are alternately even/odd.

The usa is an episode of brickleberry/ paradise PD mixed with ugly americans and superjail XD all we need is a hint of ATHF now